#### xr-nut

##### GROUP W BENCH

I sold my tractor that was used for mowing, snow, generator and lifting duties. It was a 45hp NH boomer. It couldn't lift enough weight for what I needed here at work. Bought an 85hp Mahindra that would lift the weight needed, but was just too big to haul on my car trailer back and forth from home to the office. I need something I can move between the two places easily for snow removal and general help lifting heavy stuff. So I sold the Mahindra and bought a skid loader.

Skid loader is a NH L228. I need/want to build a solution to run my pto generator off of it. So, heres the question part:

Skid loader has "standard hydraulics" and the specs are

I googled hp needed to run a 25kw generator and it threw up 35hp+, which jives because I ran that geny on the 45hp tractor for 8 days straight without issue. (1gpm of fuel)

I found this online:

Since my machine is 3000psi, I put that in the equation and came up with 26.3 gpm is what I need to for a hyd motor, does that sound right? I am not finding a hyd motor that can output 4670in-lbs continous in that gpm range.

And while you've got your thinking caps on, will this machine handle running a geny for hours, if not days on end?

Pic of machine for reference:

Skid loader is a NH L228. I need/want to build a solution to run my pto generator off of it. So, heres the question part:

Skid loader has "standard hydraulics" and the specs are

Pump flow, Standard Flow, gpm (Lpm) | 24.2 (91.5) |

Relief pressure, psi (bar) | 3046 (210) |

I found this online:

*To operate at 540 RPM you are probably looking at a LHST (Low Speed High Torque) since most motors don't run at that low RPM real well.*

Figure approximate motor size.

40 HP = 390 ft-lbs torque = 4670 in-lbs torque

Fluid motor size formulae:

(torque (in-lbs) x 6.28) / PSI = Fluid motor displacement in cubic inches per revolution

(4670 x 628) / 2000 = 14.67 CIR

figure 15% efficient so 14.67 * 1.15 = 16.9 CIR

figure inlet GPM at 540 RPM (16.9 x 540) / 231 = 39.5 GPMFigure approximate motor size.

40 HP = 390 ft-lbs torque = 4670 in-lbs torque

Fluid motor size formulae:

(torque (in-lbs) x 6.28) / PSI = Fluid motor displacement in cubic inches per revolution

(4670 x 628) / 2000 = 14.67 CIR

figure 15% efficient so 14.67 * 1.15 = 16.9 CIR

figure inlet GPM at 540 RPM (16.9 x 540) / 231 = 39.5 GPM

Since my machine is 3000psi, I put that in the equation and came up with 26.3 gpm is what I need to for a hyd motor, does that sound right? I am not finding a hyd motor that can output 4670in-lbs continous in that gpm range.

And while you've got your thinking caps on, will this machine handle running a geny for hours, if not days on end?

Pic of machine for reference:

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