I've been thinking about something for awhile now. (Dangerous I know) I would like to know the angle that my project truck could take on a side hill without tipping over. I'd like to make an inclination meter for the dash. I think I could devise a test to determine the angle, but it would be kind of a PITA to do. Then I got wondering if you couldn't figure it out with some scales. Let me explain.

Lets say we have a hypothetical vehical. For this discussion, we'll say the tires are "rock hard" and the axles are bolted to the frame. (No suspension) It is 6' wide from the outside of the tire treads. It weighs 4000 lbs. it has perfect weight distribution and the CG is 3' off the ground. If we tip one side up 45 degrees, there will be 4000 lbs. on the two downside tires and no weight on the upside tires. If we were to tip it 46 degrees, it would rollover. First, does everybody agree this would be true? If not, explain.

Assuming this is correct, I'm thinking that we could work backwards by weighing the machine flat on the ground and then again with one side tipped up a fixed amount. Let's say 15 degrees. A certain amount of weight would transfer to the low side tires. I'm thinking that we could make a calculator that we could feed in the total weight and the weight transfer and it could tell us how high the CG is and the ultimate "tipover" angle.

I realize that angle would be less because the "real world" tires at low psi and soft suspension would increase the weight transfer, but it should be close.

Now, I think I could come up with an equation to accomplish this, but it would be nice if one of you "computer wiz" guys could make a calculator that we just feed the data in like a link calculator or the ratio calculator.

PS, I think the mods here should put sticky for the link calculator and the "Grim Jeeper" ratio calculator. If this works out, it also could be put in a sticky.

Comments and flames welcome.

Lets say we have a hypothetical vehical. For this discussion, we'll say the tires are "rock hard" and the axles are bolted to the frame. (No suspension) It is 6' wide from the outside of the tire treads. It weighs 4000 lbs. it has perfect weight distribution and the CG is 3' off the ground. If we tip one side up 45 degrees, there will be 4000 lbs. on the two downside tires and no weight on the upside tires. If we were to tip it 46 degrees, it would rollover. First, does everybody agree this would be true? If not, explain.

Assuming this is correct, I'm thinking that we could work backwards by weighing the machine flat on the ground and then again with one side tipped up a fixed amount. Let's say 15 degrees. A certain amount of weight would transfer to the low side tires. I'm thinking that we could make a calculator that we could feed in the total weight and the weight transfer and it could tell us how high the CG is and the ultimate "tipover" angle.

I realize that angle would be less because the "real world" tires at low psi and soft suspension would increase the weight transfer, but it should be close.

Now, I think I could come up with an equation to accomplish this, but it would be nice if one of you "computer wiz" guys could make a calculator that we just feed the data in like a link calculator or the ratio calculator.

PS, I think the mods here should put sticky for the link calculator and the "Grim Jeeper" ratio calculator. If this works out, it also could be put in a sticky.

Comments and flames welcome.

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